Coursework - Reinforced concrete structures of the cross frame of a single-storey industrial building

Contents

Contents

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1. General Data                                                     

2. Cross Frame Layout                                       

3. Determining Frame Loads                                       

4. Static Cross Frame Calculation                                

5. Column Calculation and Design                                    

6. Design of reinforced concrete truss                              

7. Foundation Calculation and Design                               

8. List                                                 of literature

1. Design Input

      The one-story frame industrial building has a size in plan 7236m (two spans of 18 meters each), the pitch of the extreme columns is 6m and the pitch of the middle columns is 12m. The length of the temperature block is 36 m. The construction site of Tomsk. Walls are curtain panels. The building has two bridge cranes in each span with a carrying capacity of 30 tons. The pitch of the extreme columns and the pitch of the rafters coincide. The elevation of the bottom of the rafters is 12.2 m (from the layout level).

    You want to calculate and design the following subassemblies:

Rafters

Extreme columns

Foundation for extreme column

Cross Frame Layout

As the main bearing structure of the coating, one chooses a frictionless reinforced concrete truss of arched shape with a span of 18 m with a pre-stressed lower stretched belt. No lighting arrangement is provided. Reinforced concrete ribbed slabs with a size of 3 * 6 m. Reinforced concrete crane beams pre-stressed with a height of 1.0 m, the height of the crane track is 0.15  m.

       Distance from crane rail head to bottom of coating structures: 

h = 2.65 m. Distance from the level of the clean floor to the level of the crane rail head 9.55 m. Height of the crane H1 and the crane parts H2 of the column at the height of the crane 2750 mm in the span: H1 = 9,551,00,15,+,0,15 = 8.55 m, H2 = 3.8 m, H = H1 + H2 = 8.55 + 3.8 = 12, 35m. At depth of column closing in foundation hf = 0.9 m its total height Htot = 8.55 + 3.8 + 0.9 = 13.25 m.

Static Cross Frame Calculation

     General provisions. To identify the greatest possible forces in column sections, the transverse frame is calculated separately from each type of loading, first for the effect of snow and crane loads, which allows using some of these data when calculating the frame for the effect of constant load .

     The transverse frame is calculated for the following types of loads: 

1-constant loads;

2- snow load on AB span coverage;

3- crane load Dmax on column along axis A 

4- the same, B from two close cranes in AB span;

5 of the same, from four in SB and FP flyovers;

6-crane load Pbr on the column along axis A, acting from left to right and from right to left;

       7the same, to the column along the axis B from the side of SB span;

       8 wind load acting from left to right;

       9 wind load acting from right to left.

To calculate column sections, the greatest possible forces (bending moments and longitudinal forces) are determined in four column height sections:

at the  top of the column - section 1-1;

 directly above the crane cantilever - section 2-2;

 directly under the crane cantilever - section 3-3;

at the  top of the foundation (the place where the column was closed) - section 4-4.

     For the last section, the transverse force necessary for calculating the foundations for the columns is found.

     When determining forces, the following sign rule is adopted:

a) the bending moment is positive if it causes tensile stresses on the left side of the column, and negative if it is on the right;

b) the transverse force at the top of the foundation is positive if the horizontal reaction in the seal is directed from right to left, and negative if the reaction is directed from left to right.

     Geometric characteristics of columns. Geometric characteristics of columns required for static calculation of transverse frame are calculated.

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