Calculation of losses from evaporation from large breaths of the tank

Variant No. 5

Practical work No. 2

"Calculation of losses of petroleum products from evaporation from tanks from" big breath "

For the data of the task "Calculation of losses of petroleum products from evaporation from tanks from" small breaths, "determine the losses of gasoline during" large breath. " Gasoline is pumped into the tank with a capacity of Q, m3/h, from Nvzl 1 bursting height to Nvzl 2, m. The average gasoline temperature is Tp.sr = 298 K. The tank downtime is tp.p. Pumping is carried out during the day in clear sunny weather.

Determine the loss of gasoline from "small breaths" on the 1st of September from the PVS5000 tank located in the city of Yekaterinburg. Tank diameter D = 22.79 m, hull height H = 11.85 m, roof cone height Nc = 0.57 m,

(variant data):

take-off height - Nvzl = 5.20 m .

geographic latitude of the city - ψ = 56 °52"

maximum air temperature - Tmax = 293 K

minimum air temperature - Tvmin = 281 K

The duration of the day? = 17.5 h. The tank is painted with aluminum paint (blackness degree? = 0.5). Load of respiratory valves pK.V. = 196.2 Pa, pK.D. = 1962 Pa. Atmospheric pressure pa = 101200 Pa. Sunny weather (γ = 0.7). Boiling point of gasoline Tnk = 311 K, density of gasoline α20 = 0.730 t/m3. Gasoline was pumped out of the tank 27 hours ago from the bursting level of 11 m to 5.20 m. The pumping capacity is 550 m3/h. Number of valves NDKM200 n = 2, valve nozzle diameter d = 200 mm.

Rezervuar_RVS-5000.cdw